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Question

If a and b are vectors in space given by a=^i2^j5 and b=2^i+^j+3^k14, then find the value of (2a+b)[(a×b)×(a2b)].

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Solution

ab=15×214+(25)×114=270270=0|a|=(15)2+(25)2=1+45=1b=(214)2+(114)2+(314)2=4+1+914=1(2a+b)[(a×b)×(a2b)]=(2a+b)[(a2b)×(a×b)](a×b=b×a)=(2a+b)[{(a2b).b}a{(a2b)a}b]=(2a+b)[(ab2bb)a(aa2ba)b]=(2a+b)[2b2a(|a|2)b](bb=b2,ab=ba)=(2a+b)[2ab]=(2a+b)(2a+b)=4(aa)+bb+4ab=4×1+1+0=5

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