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Question

If a=^i2^j3^k,b=2^i+^j^k,c=^i+3^j2^k, and a×(b×c)=p^i+q^j+r^k, then p+q+r=

A
4
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B
4
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C
2
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D
2
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Solution

The correct option is C 4
b×c
=^i+3^j+5^k ...(using determinants).
a×(b×c)
=(^i2^j3^k)×(^i+3^j+5^k)
=^i8^j+5^k
=p^i+q^j+r^k
Hence
p+q+r=18+5
=4

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