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Question

If a=^i+^j+2^k and b=3^i+2^j^k, find the value of (a+3b).(2ab)

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Solution

b'
a=^i+^j+2^k
b=3^i+2^j^k
2a=2^i+2^j+4^k
2ab=2^i+2^j+4^k(3^i+2^j^k)=^i+0^j+5^k
3b=9^i+6^j3^k
a+3b=^i+^j+2^k+9^i+6^j3^k=10^i+7^j^k
Therefore,
(a+3b)(2ab)
=(^i+0^j+5^k)(10^i+7^j^k)
=10+05=15
'

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