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Question

If a=^i+^j2^k, b=2^i^j+^k and c=3^i^k then, find the scalars m and n such that c=ma+nb

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Solution

a=^i+^j2^k;b=2^i^j+^k&c=3^i^k
Given c=m^a+n^b
3^i^k=m(^i+^j2^k)+n(2^i^j+^k)
3^i^k=(m+2n)^i+(mn)^j+(n2m)^k
Comparing coefficients,
m+2n=3
mn=0
2m+n=1
m=1,n=1.
Hence, the answer is m=1,n=1.


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