If →a satisfies →a×(ˆi+2ˆj+ˆk)=ˆi−ˆk, then →a is equal to
A
λˆi+(2λ−1)ˆi+λˆk,λ∈R
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B
λˆi+(1−2λ)ˆj+λˆk,λ∈R
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C
λˆi+(2λ+1)ˆj+λˆk,λ∈R
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D
λˆi−(1+2λ)ˆj+λˆk,λ∈R
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Solution
The correct option is Bλˆi+(2λ+1)ˆj+λˆk,λ∈R →a×(ˆi+2ˆj+ˆk)=ˆi−ˆk=(ˆj×(ˆi+2ˆj+ˆk)) or (→a−ˆj)×(ˆi+2ˆj+ˆk)=→0 or →a−ˆj=λ(ˆi+2ˆj+ˆk) or →a=λˆi+(2λ+1)ˆj+λˆk,λ∈R