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Question

If a×b=c,b×c=a, then find value of |3a+4b+12c| if a,b,c are vectors of same magnitude.

A
11
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B
12
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C
13
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D
14
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Solution

The correct option is A 13
According to given condition,

All three vectors a,b,c are mutually perpendicular vectors with same magnitude=1

So,
|3a+4b+12c|=(|3a|2+|4b|2+|12c|2

=> 9+16+144

=> 169

=> 13

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