If $\to A, \to B$ and $\to C$ have scalar magnitudes of $5, 4, 3$ units respectively, then the angle between $\to A$ and $\to C$ is:

{cos}^{- 1} (3 / 5)

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{cos}^{- 1} (4 / 5)

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π / 2

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{sin}^{- 1} (3 / 4)

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Solution

The correct option is A ${cos}^{- 1} (3 / 5)$
Let angle between A and C be $θ$ so that $A cos θ = C$ .
That gives $θ = {cos}^{- 1} (3 / 5)$ .
Please note that A, B and C form the sides of a right angled triangle with A as the hypotenuse.

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