If - A - B - A - vecB- then angle between A and B will beA- 60- B- 90-C- 120-D- 0-

The correct option is D 0^∘ Resultant of two vectors A⃗ and B⃗ can be given by R⃗=A⃗+B⃗ |R⃗|=|A⃗+B⃗|=√(A^2+B^2+2AB cos θ) If θ =0^∘ then |R⃗|=A+B =|A⃗|+|B⃗| ...

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Byju's Answer

Standard XII

Physics

Vector Addition

If | A + B |=...

Question

If $| \to A + \to B | = | \to A | + | v e c B$ , then angle between $\to A$ and $\to B$ will be

90^{\circ}

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120^{\circ}

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0^{\circ}

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60^{\circ}

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Solution

The correct option is C $0^{\circ}$

Resultant of two vectors $\to A$ and $\to B$ can be given by $\to R = \to A + \to B$
$| \to R | = | \to A + \to B | = \sqrt{A^{2} + B^{2} + 2 A B c o s θ}$
If $θ = 0^{\circ} t h e n | \to R | = A + B = | \to A | + | \to B |$

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If |→A+→B|=|→A|+|vecB, then angle between →A and →B will be

The correct option is C 0∘ Resultant of two vectors →A and →B can be given by →R=→A+→B |→R|=|→A+→B|=√A2+B2+2ABcosθ If θ=0∘then|→R|=A+B=|→A|+|→B|

If $| \to A + \to B | = | \to A | + | v e c B$ , then angle between $\to A$ and $\to B$ will be

The correct option is C $0^{\circ}$

Resultant of two vectors $\to A$ and $\to B$ can be given by $\to R = \to A + \to B$
$| \to R | = | \to A + \to B | = \sqrt{A^{2} + B^{2} + 2 A B c o s θ}$
If $θ = 0^{\circ} t h e n | \to R | = A + B = | \to A | + | \to B |$