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Trigonometric Ratios of Standard Angles

If A⃗=B⃗ + ...

Question

If $\to A = \to B + \to C$ and the magnitude of $A, B$ and $C$ are $5, 4$ and $3$ minutes respectively,then the angle between $A$ and $C$ is:

c o s^{- 1} (4 / 5)

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c o s^{- 1} (3 / 5)

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t a n^{- 1} (3 / 4)

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s i n^{- 1} (3 / 5)

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Solution

The correct option is B $c o s^{- 1} (3 / 5)$
$¯ A = ¯ B + ¯ C$ forms a right angle triangle. Where $A = 5$ , $B = 4$ , $C = 3$
From the figure, Let Angle between $¯ A$ and $¯ C$ is $θ$ .
$c o s (θ) = \frac{3}{5}$ $\Rightarrow θ = c o s^{- 1} (\frac{3}{5})$

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If →A=→B+→C and the magnitude of A,B and C are 5,4 and 3 minutes respectively,then the angle between A and C is:

The correct option is B cos−1(3/5)¯A=¯B+¯C forms a right angle triangle. Where A=5, B=4, C=3From the figure, Let Angle between ¯A and ¯C is θ.cos(θ)=35 ⇒θ=cos−1(35)

If $\to A = \to B + \to C$ and the magnitude of $A, B$ and $C$ are $5, 4$ and $3$ minutes respectively,then the angle between $A$ and $C$ is:

The correct option is B $c o s^{- 1} (3 / 5)$
$¯ A = ¯ B + ¯ C$ forms a right angle triangle. Where $A = 5$ , $B = 4$ , $C = 3$
From the figure, Let Angle between $¯ A$ and $¯ C$ is $θ$ .
$c o s (θ) = \frac{3}{5}$ $\Rightarrow θ = c o s^{- 1} (\frac{3}{5})$