If a-b-c- are non-zero vectors such that -a-b-c-a-b-c- then -a-b-c-2-

The correct option is D |#160;a|^2+|#160;b|^2+|#160;c|^2 ( nbsp; a^2 amp; a.b amp; nbsp;a.c nbsp;b.a amp; b^2 amp; nbsp;b.c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Binomial Theorem

If a⃗,b⃗,c⃗...

Question

If $\to a, \to b, \to c$ are non-zero vectors such that $| (\to a \times \to b) . \to c | = | \to a | | \to b | | \to c |$ , then $| \to a + \to b + \to c |^{2} =$

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| \to a |^{2} + | \to b |^{2} + | \to c |^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to a, \to b, \to c

\to b \times \to c = \to a

\to a \times \to b = \to c

\to c \times \to a = \to b

\to a, \to b, \to c

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a + \to b + \to c =

\to a + \to b + \to c = 0

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a, \to b, \to c

(\to a \times \to b) \times \to c = \to a \times (\to b \times \to c)

\to a, \to b

\to c

\to a . \to b \neq 0, \to b . \to c \neq 0

\to a

\to c

\to a, \to b, \to c

\to b \times \to c = \to a, \to c \times \to a = \to b

\to a \times \to b = \to c

Join BYJU'S Learning Program