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Question

If a,b,c are three non- coplanar vectors for which [abc] a,b,c constitute the reciprocal system of vectors, then any vector r can be expressed as

A
r=(r×a).a+(r×b).b+(r×c).c
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B
r=(r×a).a+(r×b).b+(r×c).c
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C
r=(r.a).a+(r.b).b+(r.c).c
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D
r=(r.a)a+(r.b)b+(r.c)c
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Solution

The correct option is C r=(r.a)a+(r.b)b+(r.c)c
Let r be expressed as a linear combination of the non-coplanar
vector a,b,c in the form
r=xa+yb+zc ...(1)
where x,y,z are some scalar
Multiplying both sides of (1) scalarly with b×c, we get
r(b×c)=xa(b×c)+yb(b×c)+zc(b×c)=x[abc]+y[bbc]+z[cbc]=x[abc]
Since [bbc]=0=[cbc]
x=r(b×c)[abc]=r(b×c)[abc]=ra, since a=b×c[abc]
Similarly multiplying both sides of (1) scalarly with c×a and a×b, we can show that
y=rb and z=rc
Substitute the values of x,y and z in (1) , we get
r=(ra)a+(rb)b+(rc)c

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