If a- -b- -c- are unit vectors such that a- -b- -c- -0- and a- -b- - 3- then - a-b- - b-c- - c-a- -

The correct option is C 3√( 3 ) 2 |a⃗|=|b⃗|=|c⃗|=1 = gt; position vectors A,B,C of a⃗, b⃗, c⃗ lie on a circle of radii 1, and origin as centr ...

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Applications of Cross Product

If a⃗ ,b⃗ ,...

Question

If $\to a, \to b, \to c$ are unit vectors such that $\to a + \to b + \to c = \to 0$ and $(\to a, \to b) = \frac{π}{3}$ , then $∣ ∣ \to a \times \to b ∣ ∣ + ∣ ∣ \to b \times \to c ∣ ∣ + | \to c \times \to a | =$

\frac{3}{2}

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\frac{3 \sqrt{3}}{2}

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Solution

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Similar questions

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

\to a, \to b, \to c

\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b

| \to a | = | \to b | = | \to c |

| \to a | = 1, ∣ ∣ \to b ∣ ∣ = \sqrt{2}

| \to c | = \sqrt{3}

\to a ⊥ (\to b + \to c)

\to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

∣ ∣ \to a + \to b + \to c ∣ ∣

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

\to a, \to b, \to c

\to a

\to b

\to c

\to b

\to c

\frac{π}{3}

| \to a +

\to b +

\to c |

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