If a- b- c- are vectors show that a- - b- - c- - 0 and - a- - - 3- - b- - - 5- - c- - - 7 then angle between vector b- and c- is

The correct option is D 90Given, a⃗, b⃗, c⃗ are vectors #10; #10; a⃗+b⃗+c⃗=θ #10; #10; |a⃗|=3,|b⃗|=5,|c⃗|=7 #10; #10;To find : angle ...

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Addition and Subtraction in Unit Vector Notation

If a⃗, b⃗...

Question

If $\to a$ , $\to b$ , $\to c$ are vectors show that $\to a$ + $\to b$ + $\to c$ = 0 and
$| \to a |$ = 3, $∣ ∣ \to b ∣ ∣$ = 5, $| \to c |$ = 7 then angle between vector $\to b$ and $\to c$ is

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\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a, \to b, \to c

\to a, \to b, \to c

\to a \times \to b = \to b \times \to c = \to c \times \to a

[\to a \to b \to c] = 0.

\to a, \to b, \to c

\to a + \to b + \to c = \to 0,

\to a \times \to b = \to b \times \to c = \to c \times \to a,

[\to a \to b \to c] = 0.

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

∣ ∣ \to a \times \to b ∣ ∣ + ∣ ∣ \to b \times \to c ∣ ∣ + | \to c \times \to a | =

\to a, \to b, \to c

\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b

| \to a | = | \to b | = | \to c |

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