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Question

If u=a×(b×c)+b×(c×a)+c×(a×b), then u=

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Solution

u=a×(b×c)+b×(c×a)+c×(a×b)
u=(a.c)b(a.b)c+(a.b)c(b.c)a+(b.c)a(a.c)b
u=0

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