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Question

If u=ab and v=a+b and |a|=|b|=2, then |u×v|=


A

216(a.b)2

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B

16(a.b)2

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C

24(a.b)2

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D

4(a.b)2

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Solution

The correct option is A

216(a.b)2


|u×v|=|(ab)×(a+b)|=|2a×b|=2 |a||b| sin θ=8 sin θ=81cos2 θ=81(a.b4)2 (a.b=4 cos θ)=216(a.b)2


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