If volume of cube is $64 c m^{3}$ , find its surface area.

Open in App

Solution

Let $a$ be the side of the cube.
Then given $a^{3} = 64$
or, $a = 4$ .
Then its surface area will be $6 \times a^{2} = 6 \times 16 = 96$ cm $^{2}$ .

Suggest Corrections

Similar questions

486 c m^{2}

Question 11

The volume of a cube is $64 c m^{3} .$ Its surface area is
(a) $16 c m^{2}$ (b) $64 c m^{2}$
(c) $96 c m^{2}$ (d) $128 c m^{2}$

$2$ cubes each of volume $64 c m^{3}$ are joined end to end. Find the surface area of the resulting cuboids.

Join BYJU'S Learning Program