If water be used to construct a barometer, what would be the height of water column at standard atmospheric pressure i.e., 76 cm of mercury? Specific gravity of mercury = 13.6

1033.6 m

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1033.6 cm

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1033.6 mm

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103.36 cm

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Solution

The correct option is B
1033.6 cm

Simply,

$ρ_{m} g H_{m} = ρ_{w} g H_{w}$

where $H_{m}$ = Height of Mercury column

$H_{w}$ = Height of water column

$\Rightarrow \frac{ρ_{m}}{ρ_{w}} H_{w} = H_{w}$

$\Rightarrow H_{w} = (13.6) \times (76) c m$
$H_{w} = 1033.6 c m$

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If mercury is replaced with water in barometer, what would be the height of water column at standard atmospheric pressure, i.e., $76 c m$ of mercury? (Specific gravity of mercury $= 13.6$ )

Q. If water be used to construct a barometer, what would be the height of water column at standard atmospheric pressure (76 cm of mercury) ?

At a given place a mercury barometer records a pressure of 0.70m of Hg . What would be the height of water column if mercury in barometer is replaced by water ? Take density of mercury to be 13.6 ×10pawer3 kg m-3 .

Q. At a given place, a mercury barometer records a pressure of

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If water be used to construct a barometer, what would be the height of water column at standard atmospheric pressure i.e., 76 cm of mercury? Specific gravity of mercury = 13.6

The correct option is B 1033.6 cm Simply, ρmgHm=ρwgHw where Hm = Height of Mercury column Hw = Height of water column ⇒ρmρwHw=Hw ⇒Hw=(13.6)×(76) cm Hw=1033.6 cm

The correct option is B
1033.6 cm

Simply,

$ρ_{m} g H_{m} = ρ_{w} g H_{w}$

where $H_{m}$ = Height of Mercury column

$H_{w}$ = Height of water column

$\Rightarrow \frac{ρ_{m}}{ρ_{w}} H_{w} = H_{w}$

$\Rightarrow H_{w} = (13.6) \times (76) c m$
$H_{w} = 1033.6 c m$