If we add 1 to the numerator and subtract 1 from the denominator- a fraction reduces to 1- It becomes1-2 if we only add 1 to the denominator- What is the fraction-

Given, (x + 1)/(y 1) = 1 x y = 2 (1) x/(y + 1) = 1/2 2 x y = 1 (2) On (2) – (1), x=3, y = 5 ...

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Byju's Answer

Standard VIII

Mathematics

Reducing Equations to Simpler Form

If we add 1 t...

Question

If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes $\frac{1}{2}$ if we only add 1 to the denominator. What is the fraction?

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Solution

Given, $\frac{(x + 1)}{(y - 1)}$ = 1

x- y = -2 (1)

$\frac{x}{(y + 1)}$ = $\frac{1}{2}$

2 x- y = 1 (2)

On (2) – (1),

x=3, y = 5

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If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes 12 if we only add 1 to the denominator. What is the fraction?

Given, (x+1)(y−1) = 1 x- y = -2 (1) x(y+1) = 12 2 x- y = 1 (2) On (2) – (1), x=3, y = 5

If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes $\frac{1}{2}$ if we only add 1 to the denominator. What is the fraction?

Given, $\frac{(x + 1)}{(y - 1)}$ = 1

x- y = -2 (1)

$\frac{x}{(y + 1)}$ = $\frac{1}{2}$

2 x- y = 1 (2)

On (2) – (1),

x=3, y = 5