If we are pushing a wall , we are applying force but no effects of force ( like change in shape , size , direction , etc.) is seen .
Why is it so ?

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Solution

Dear student,

$B e c a u s e W o r k d o n e = F o r c e \times d i s p l a c e m e n t H e r e \sin c e d i s p l a c e m e n t = 0 s o, W o r k d o n e = F o r c e \times 0 = 0 H e n c e t h e w o r k d o n e i n p u s h i n g t h e w a l l i s z e r o .$

Regards

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Q. Action is the cause of reaction .Then , if we push the wall and wall pushes us , we are being pushed only when we push the wall . Hence here our force creates a opposite play . Then Why can't we say the force we created here's action instead of saying any of the 2 forces would be action and the other is reaction ?

Q. Suppose there are two balls of equal mass, shape and size and we apply the equal force on both ,suppose 5N but after when they stop them we see that one ball covers less distance and ball covers more, even all are same (mass,force,shape and size ) Why?

Q. Change of shape and size due to force can be seen by applying force on:

What would happen if we apply force on a matalic ball?will it change its shape?

Observation 1: Try to stop a ball coming towards you,so as to save a boundary, by applying a force of some magnitude in the opposite direction of the motion of ball.

Observation 2: In this case apply the force of same magnitude but in same direction of the motion of the ball.

In observation 1 boy saves a boundary by applying a force opposite to the direction of motion but in observation 2, the change in direction of force cost the team 4 runs as the change in direction of force pushed the ball further to the boundary.

So, the change in effect of a force can be experienced by a change in it's direction as well as magnitude. The above statement is :-

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If we are pushing a wall , we are applying force but no effects of force ( like change in shape , size , direction , etc.) is seen . Why is it so ?

Dear student, Because Work done = Force×displacementHere since displacement=0so, Work done = Force×0=0Hence the work done in pushing the wall is zero. Regards

If we are pushing a wall , we are applying force but no effects of force ( like change in shape , size , direction , etc.) is seen .
Why is it so ?

Dear student,

$B e c a u s e W o r k d o n e = F o r c e \times d i s p l a c e m e n t H e r e \sin c e d i s p l a c e m e n t = 0 s o, W o r k d o n e = F o r c e \times 0 = 0 H e n c e t h e w o r k d o n e i n p u s h i n g t h e w a l l i s z e r o .$

Regards