Question

If we can throw a ball up to a maximum height $H$, the maximum horizontal distance to which we can throw it is

• A. $2H$
• B. $\sqrt{2}H$
• C. $H$
• D. $\frac{H}{2}$

Answer 1

The correct option is A $2H$

$H=\frac{u^2}{2g}\Rightarrow u^2=2gH$

For maximum horizontal distance

$X_{max}=\frac{u^2}{g}=\frac{2gH}{g}=2H$