1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Haber Bosch Process
If we have 24...
Question
If we have 24g of nitrogen how much hydrogen atom is required to form ammonia?
Open in App
Solution
N
2
+
3
H
2
⇄
2
N
H
3
1
mole of Nitrogen requires
3
moles of Hydrogens
28
g
requies
6
g
Hydrogen.
24
g
requies
x
g
Hydrogen.
x
=
24
×
6
28
=
36
7
=
5.14
∴
5.14
Hydrogen atoms required.
Suggest Corrections
0
Similar questions
Q.
Hydrogen combines with nitrogen in a 3:14 weight ratio to form ammonia. If every molecule of ammonia contains three atoms of hydrogen and one atom of nitrogen, an atom of nitrogen must weigh :
Q.
Nitrogen combines with hydrogen in the ratio of 14 : 3 to form ammonia gas. The mass of nitrogen required to combine with 5.7 g of hydrogen is _____.
Q.
Ammonia is a common ingredient in fertilizers. How much nitrogen is required to produce
100
k
g
of ammonia in the following unbalanced reaction?
N
2
(
g
)
+
H
2
(
g
)
→
N
H
3
(
g
)
Q.
Nitrogen and hydrogen combine in the ratio of 14 : 3 by mass to form ammonia. The mass of nitrogen required to react completely with 9 g of hydrogen is
Q.
How many grams of hydrogen gas is required to produce 4.8 mol of ammonia on a reaction with an excess of nitrogen?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Hydrides of Nitrogen - Ammonia and Hydrazine
CHEMISTRY
Watch in App
Explore more
Haber Bosch Process
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app