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Question

If we have a pure MgCO3 sample that contains a total of 1.26 millimoles of electrons, the number of moles of MgCO3 present in the sample is x×105, x is.

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Solution

One molecule of MgCO3 contains =12+6+(8×3)=42 electrons.
So, number of electrons in 1 mole of MgCO3=42×6.022×1023
Therefore, 1.26 millimoles of electrons will present in
=1.26 × 103× 6.022 × 102342 × 6.022 × 1023moles=3×105 moles of MgCO3

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