wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If we have a pure Na2CO3 sample that contains a total of 7.8286×1024 electrons, then find the number of moles of Na2CO3 present in the sample.

A
0.5 moles
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.3 moles
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.7 moles
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.25 moles
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.25 moles
Total number of electrons present in one molecule of Na2CO3=(11×2)+6+(3×8)=52.
So, 52×6.022×1024 electrons are present in 1 mole of Na2CO3
Therefore, 7.8286×1024 electrons will be present in
=7.8286 × 102452 × 6.022 × 1023 moles of Na2CO3
= 0.25 moles of Na2CO3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon