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Question

If we have a pure NaNO3 sample that contains a total of 8.4 kilomoles of electrons, find the number of moles of NaNO3 present in the sample.

A
200 moles
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B
2 moles
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C
0.2 moles
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D
400 moles
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Solution

The correct option is A 200 moles
Total number of electrons present in 1 formula unit of NaNO3=11+7+24=42

So, the total number of electrons present in one mole of NaNO3=42×6.022×1023

The moles of NaNO3 that would have 8.4 kilomoles of electrons will be
=8.4 × 1000 × 6.022 × 102342 × 6.022 × 1023
= 200 moles

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