$I f x = 1 a n d y = 6 is a solution of the equation 8 x - a y + a^{2} = 0, find the values of a.$

Open in App

Solution

$x = 1, y = 6 is a solution of the equation 8 x - a y + a^{2} = 0$

Substituting the value of x and y,

$8 \times 1 - a \times 6 + a^{2} = 0 \Rightarrow 8 - 6 a + a^{2} = 0 \Rightarrow a^{2} - 6 a + 8 = 0 \Rightarrow a^{2} - 2 a - 4 a + 8 = 0 \Rightarrow a (a - 2) - 4 (a - 2) = 0 \Rightarrow (a - 2) (a - 4) = 0 Either a - 2 = 0, then a = 2 O r a - 4 = 0, then a = 4 H e n c e, a = 2, 4$

Suggest Corrections

Similar questions

x = 1, y = 1

3 x + a y = 6,

^{'} a^{'} .

If x=1,y=2 is a solution of equation a^2 x +ay =3,then find the value of a

a

x + a y = 1, a x + y =

a^{2}

x + a y = 3

a x + 4 y = 6

x > 1, y > 0

Join BYJU'S Learning Program