If $(x + 1)$ is a factor of the polynomial $(2 x^{2} + k x)$ then the value of k is
(a) -2 (b) -3 (c) 2 (d)3

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Solution

ANSWER:
(c) 2
x+1 is a factor of $2 x^{2} + k x$
So, -1 is a zero of $2 x^{2} + k x$
Thus, we have:

$2 \times (- 1)^{2} + k \times - 1 = 0 \Rightarrow 2 - k = 0 \Rightarrow k = 2$

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