Question

If $x+1$ is a factor of the polynomial $2x^2+kx$, then the value of $k$ is

• A. -3
• B. 4
• C. 2
• D. -2

Answer 1

The correct option is

C

2

$(x+1)$ is a factor of $p\left(x\right)$

$x+1=0$

$\Rightarrow x=-1$

Therefore, $p(-1)=0$

$\therefore$ $2(-1{)}^2+k(-1)=0$

$\Rightarrow$ $2-k=0\Rightarrow k=2$

Hence, the value of $k$ is $2$.