If $(x + 1, 1) = (3, y - 2)$ , find the values of $x$ and $y$ .

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Solution

$(x + 1, 1) = (3, y - 2)$

By comparing

$x + 1 = 3$

$\Rightarrow x = 3 - 1 = 2$

$1 = y - 2$

$\Rightarrow y = 2 + 1 = 3$

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(i) If $(\frac{a}{3} + 1, b - \frac{2}{3}) = (\frac{5}{3}, \frac{1}{3}),$ find the values of a and b.

(ii) If (x + 1, 1) = (3, y - 2), find the values of x and y.

(\frac{a}{3} + 1, b - \frac{2}{3}) = (\frac{5}{3}, \frac{1}{3})

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