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Question

If x=1111(20 digits), y=3333(10 digits) and z=2222(10 digits), then xz is equal to
  1. y2
  2. 2y2
  3. y3
  4. 3y3


Solution

The correct option is A y2
We know that,
x=1111(20 digits)x=9999(20 digits)9x=19(10201)y=13(10101)z=29(10101)

Now, 
xz=10209210109+19xz=(1010313)2xz=[13(10101)]2xz=y2
 

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