If x2 - 1x2 - 38-find the value of x3 - 1x3

⇒ (x 1x) ^2+2=38 ⇒ #160; (x 1x) =6 Cube on both sides #160; ⇒ x^3 1x^3 3x1x (x 1x) =216 ⇒ x^3 1x^3 3(6)=216 ⇒ #160; x^3 1x^3=234 ...

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Inequality

If x2 + 1x2...

Question

If $x^{2} + \frac{1}{x^{2}} = 38$ ,find the value of $x^{3} - \frac{1}{x^{3}}$

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