If $(x + 2)$ is a factor of the polynomial $f (x) = x^{2} + a x + 2 b$ and $a + b = 4$ , then the value of $a$ and $b$ are

a = 1

b = 3

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a = 3

b = 1

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a = - 1

b = 5

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a = 5

b = - 1

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Solution

The correct option is C $a = 3$ , $b = 1$
$(- 2)^{2} + a (- 2) + 2 b = 0$
$- 2 a + 2 b = - 4$
$a - b = 2$
$a + b = 4$
$a = 3$ , $b = 1$

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f (x) = a x + b

a

b

f (- 1) = - 5

f (3) = 3

a

b

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