If |x−2|+|x−6|=3 then the value of x is
No value for x
Given, |x−2|+|x−6|=3
For x≤2
Changing the sign throughout , we have
−(x−2)−(x−6)=3
−x+2−x+6=3
−2x+8=3
−2x=3−8
−2x=−5
⇒x=52
This is not possible since x≤2
For x≥6
x−2+x−6=3
2x−8=3
2x=3+8
⇒x=112
This is not possible since x≥6
Therefore no values for x which satisfy the given equation.