wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x2 + y2 = 14 and xy = 3, find the value of 2(x+y)25(xy)2.


A

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

106

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

52

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

0


2(x2 + y2 +2xy)5(x2 - 2xy + y2)
= 2x2 +2y2 + 4xy - 5x2 + 10xy - 5y2
= -3x2 - 3y2 + 14xy
= -3(x2 +y2) + 14xy
= (-3 × 14) + (14 × 3)
= - 42 + 42
= 0


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon