You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Triple Product

If x-2y=0 a...

Question

If $x - 2 y = 0$ and $y^{2} - 4 x = 0$ intersects (for all $x > 0$ ), then $x =$

13.65

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

17.28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $16$
$x = 2 y$ & $y^{2} = 4 x$

But $\frac{x}{2} = y$ in $y^{2} = 4 x$

$\Rightarrow x^{2} = 16 x$

$\Rightarrow x = 16$

$(∵ x > 0)$ .

Suggest Corrections

Similar questions

x - 2 y - 1 = 0

x^{2} + y^{2} + 4 x - 2 y - 5 = 0

P

Q

\sqrt{5} P Q

x^{2} + y^{2} - 2 x - 4 y + 4 = 0

x + 2 y = 4

x + 2 y = 0

x + 2 y + a = 0

x^{2} + y^{2} - 4 = 0

A

B

12 x - 6 y - 41 = 0

x^{2} + y^{2} - 4 x - 2 y + 1 = 0

C

D

A, B, C

D

a

x^{2} + y^{2} - 4 x + 2 y + 3 = 0, x^{2} + y^{2} - x + 4 y + 4 = 0

x^{2} + y^{2} + 2 g x + 5 + 7 = 0

(- 1, 1)

g =

The equation of the circle which intersects circles $x^{2} + y^{2} + x + 2 y + 3 = 0, x^{2} + y^{2} + 2 x + 4 y + 5 = 0$ and

$x^{2} + y^{2} - 7 x - 8 y - 9 = 0$ at right angle, will be

Join BYJU'S Learning Program