If x-3sint - y-3cost - then find dydx at t- 3-

x=3sin t Differentiating w.r.t. t, we get, dxdt=3cos t y=3cos t Differentiating w.r.t. t, we get, dydt= 3sin t Thus, dydx= tan t At ...

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Parametric Differentiation

If x=3sint ...

Question

If $x = 3 sin t, y = 3 cos t,$ then find $\frac{d y}{d x}$ at $t = \frac{π}{3}$ .

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y = {(tan x)}^{{(tan x)}^{tan x}}

\frac{d y}{d x}

x = \frac{π}{4}

x^{2} + y^{2}

x = a s i n 2 t (1 + c o s 2 t)

y = b c o s 2 t (1 - c o s 2 t),

\frac{d y}{d x}

t = \frac{π}{4}

t = \frac{π}{3} .

A :

x = c t, y = \frac{c}{t}

t = 1, \frac{d y}{d x} =

B :

x = 3 cos θ - {cos}^{3} θ, y = 3 sin θ - {sin}^{3} θ

θ = \frac{π}{3}, \frac{d y}{d x} =

C :

x = a (t + \frac{1}{t}), y = a (t - \frac{1}{t})

t = 2, \frac{d y}{d x} =

D :

log (sec x)

tan x

x = \frac{π}{4}

Find $\frac{d y}{d x}$ at $t = \frac{π}{4}$ if $y = {cos}^{4} t$ & $x = {sin}^{4} t$ .

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