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Question

If x=4t2+5,y=6t2+7t+3, find d2ydx2.

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Solution

Differentiate x=4t2+5 with respect to t,

dxdt=8t

Again differentiate with respect to t,

d2xdt2=8 (1)

Differentiate y=6t2+7t+3 with respect to t,

dydt=12t+7

Again differentiate with respect to t,

d2ydt2=12 (2)

Divide equation (2) by equation (1),

d2ydx2=128

d2ydx2=32


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