If (x + 5) and (x – 3) are the factors of $a x^{2} + b x + c$ , then values of a, b and c are

1, 2, 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, −2, 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, 2, −15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1, 2, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1, 2, −15
$(x + 5) (x - 3) = x^{2} + (5 - 3) x + (5) (- 3) = x^{2} + 2 x - 15 c o m p a r e w i t h a x^{2} + b x + c a = 1, b = 2 a n d c = - 15$

Correct Option: d) 1, 2, −15

Suggest Corrections

Similar questions

If both $(3 x + 2)$ and $(x + 3)$ are factors of $a x^{2} + b x + c$ then find the value of $a + b + c$ .

(x + 3)

(x + \frac{1}{3})

a x^{2} + b x + 5

10 a - 3 b + 1

(x - 1)

(x - 2)

p (x) = x^{3} + a x^{2} + b x + c

a + b = 1

b

‘p’ and ‘q’ are the zeroes of the polynomial $a x^{2} + b x + c = 0$ .

(x-p) and (x-q) are the only factors of the expression $a x^{2} + b x + c$ ,

The values of $a$ and $b$ are:

Join BYJU'S Learning Program