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Question

# ‘p’ and ‘q’ are the zeroes of the polynomial ax2+bx+c=0. (x-p) and (x-q) are the only factors of the expression ax2+bx+c, The values of a and b are:

A

-1, -(p + q)

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B

1, p + q

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C

1, -(p+q)

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D

-1, -(p+q)

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Solution

## The correct option is C 1, -(p+q) Since, ‘p’ and ‘q’ are the zeroes of the polynomial ax2+bx+c, (x-p) and (x-q) are the factors of the expression ax2+bx+c, so ax2+bx+c=(x−p)(x−q) ⟹ax2+bx+c=x2−(p+q)x+pq By comparing the co-efficients of x2, x and the constant term,we get a=1, b=−(p+q) and c=pq

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