If X=[8n−7n−1/nϵN] and Y=[49(n−1)/nϵN], then
If X = { 8n−7n−1:n ϵ N } and Y = {49(n−1):n ϵ N}, then prove that X⊆Y.
if X = {\(8^n-7n-1/n \in N\)} and Y = {\(49(n-1)/n \in N\)}, then
If X={8n−7n−1| n ϵ N} and Y={49n−49| n ϵ N}, then