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Question

If x=a+bi is a complex number such that x2=3+4i and x3=2+11i, where i=1, then (a+b) equal to

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Solution

given that x2=3+4i ...(1)

and x3=2+11i ...(2)

Dividing (2) by (1), we get

x=2+11i3+4i=(34i)(2+11i)32+42=50+25i25=a+bi

Therefore, a+b=3


Ans: 3


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