If x - a sin - t - -6- and x- - a cos - t- then what is the phase difference between the two waves-

X = a sin ( ω t + π/6 ) x' = a cos ω t = a sin ( ω t + π/2 ) Therefore, phase difference = ( π/2 ) π/6 = ( π/3 ) ...

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Phase Difference

If x = a sin ...

Question

If $x = a s i n [ω t + \frac{π}{6}] a n d x^{'} = a c o s ω t$ , then what is the phase difference between the two waves?

$\frac{π}{3}$

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$\frac{π}{6}$

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$\frac{π}{2}$

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$π$

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x = a sin (ω t + π / 6)

x^{'} = a cos ω t

If $x = a s i n [ω t + \frac{π}{6}] a n d x^{'} = a c o s ω t$ , then what is the phase difference between the two waves?

If $x = a s i n (ω t + \frac{π}{6})$ and $x = acoswt$ then what is the phase difference between the two waves?

y_{1} = A_{0} s i n (k x - ω t), y_{2} = 3 \sqrt{2} A_{0} s i n (k x - ω t + ϕ)

y_{3} = 4 A_{0} c o s (k x - ω t)

0 \leq ϕ \leq π / 2

π / 4

ϕ

If $x = a s i n (ω t + \frac{π}{6})$ and $x = acoswt$ then what is the phase difference between the two waves?

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