If x-cos 3- y-sin 3- then -1-d y-d x2-

The correct option is B x=cos^3θ,y=sin^3θ⇒dy/dx= tanθ ...

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Implicit Differentiation

If x=cos 3θ, ...

Question

$I f x = c o s^{3} θ, y = s i n^{3} θ t h e n \sqrt{1 + {(\frac{d y}{d x})}^{2}} =$

secθ

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sec²θ

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cotθ

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Solution

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Similar questions

x = 3 cos θ - cos 3 θ

y = 3 sin θ - sin 3 θ,

\frac{d y}{d x}

x = cos θ, y = {sin}^{3} θ, t h e n {(\frac{d y}{d x})}^{2} + y \frac{d^{2} y}{d x^{2}}

θ = \frac{π}{2}

\frac{{sin}^{3} θ + {cos}^{3} θ}{sin θ + cos θ} + \frac{{sin}^{3} θ - {cos}^{3} θ}{sin θ - cos θ} = K

A :

x = c t, y = \frac{c}{t}

t = 1, \frac{d y}{d x} =

B :

x = 3 cos θ - {cos}^{3} θ, y = 3 sin θ - {sin}^{3} θ

θ = \frac{π}{3}, \frac{d y}{d x} =

C :

x = a (t + \frac{1}{t}), y = a (t - \frac{1}{t})

t = 2, \frac{d y}{d x} =

D :

log (sec x)

tan x

x = \frac{π}{4}

s i n θ - c o s θ = 1

s i n^{3} θ - c o s^{3} θ

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