Question

If $x-\frac{1}{x}=6$, find the value of
$x^2+\frac{1}{x^2}$

Answer 1

We have,

$x-\frac{1}{x}=6$

On squaring both sides, we get

$x^2+\frac{1}{x^2}-2=36$

$x^2+\frac{1}{x^2}=38$

Hence, this is the answer.