We have,
xx=1
⇒x=x
Suppose that,
00=1
Hence,0=1×0
therfore,
2×0=1×0
⇒2×0=0
so,
21=00
thus,
2=1
Hence, this is the answer.
If x/y+y/x=-1 (x is not equal to y,x is not equal to 0,y is not equal to 0 ) what will be value of x^3-y^3
Let a1 not equal to a2 not equal to 0. f(x) = a1x2+b1x+c1 and g(x) = a2x2+b2x+c2. If p(x) = f(x) - g(x). If p(x) =0 for x= - 1 only and p(-2)=2 then what is the value of p(2)?
Given that If x is not equal to y , the (x,y) is not equal to (y,x) But if x = y , the (x,y ) = ( y,x)