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Question

If xϵR and nϵI, then the determinant Δ=∣ ∣ ∣sin(nπ)sinxcosxlog(tanx)cosxsinxcos[(2n+1)π2]log(cotx)log(cotx)log(tanx)tan(nπ)∣ ∣ ∣


A

sin(π4x)

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B

tan(π4x)

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C

log(tanx)log(cotx)

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D

0

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Solution

The correct option is D

0


We can write Δ as

Δ=∣ ∣ ∣0sinxcosxlog(tanx)(sinxcosx)0log(tanx)log(tanx)log(tanx)0∣ ∣ ∣

=(1)3∣ ∣ ∣0(sinxcosx)log(tanx)sinxcosx0log(tanx)log(tanx)log(tanx)0∣ ∣ ∣ [taking 1 common from R1, R2 and R3]

=Δ

2Δ=0Δ=0


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