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Question

If x(0,1) then value of tan1(1x22x)+cos1(1x21+x2) is?

A
π2
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B
π2
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C
0
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D
π
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Solution

The correct option is A π2
tan1(1x22x)+cos1(1x21+x2)
Put x=tanθ
=tan1(cot2θ)+cos1cos2θ
=tan1(tan(π22θ))+2θ
=π22θ+2θ
=π2

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