If x is a positive integer such that the distance between points P (x, 2) and Q (3, –6) is 10 units, then x =

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-3

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-9

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Solution

The correct option is C
9

$\sqrt{(3 - x)^{2} + (6 + 2)^{2}} = 10$
$(3 - x)^{2} + (6 + 2)^{2} = 100$
$(3 - x)^{2} = 36$
3 - x = ± 6
x = -3 or 9

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