If x is a prime number, then the solution set of the inequation x3−2≥x2−5 is:
[1 Mark]
A
x={2, 3, 5}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x={2, 3, 5, 7}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x={2, 3, 5, 7, 11, 13}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x={2, 3, 5, 7, 11, 13, 17}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D x={2, 3, 5, 7, 11, 13, 17} Given, x3−2≥x2−5
where x is a prime number ⇒x3−x2≥2−5 ⇒2x−3x6≥−3 ⇒−x6≥−3 ⇒x6≤3 ⇒x≤18 Since x is a prime number, ∴x={2,3,5,7,11,13,17}