If x is equal to 41 and y is equal to 3, then what is the value of x-9y?
Find the value of the given expression
Given, x=41 and y=3
On substituting the values of x and y in x-9y, we get,
=x-9y=41−(9×3)=41−27=14
Hence, the value of x-9y is 14.
If x/y+y/x=-1 (x is not equal to y,x is not equal to 0,y is not equal to 0 ) what will be value of x^3-y^3