If 'x' is the specific resistance of the electrolyte solution and 'y' is the molarity of the solution, then $\land_{m}$ is given by :

\frac{1000 x}{y}

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\frac{1000 y}{x}

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\frac{1000}{x y}

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\frac{x y}{1000}

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Solution

The correct option is D $\frac{1000}{x y}$
Specific resistance= x
Specific conductance = $\frac{1}{x}$
Molarity = y
Therefore, $Molar conductivity = \frac{specific conductance \times 1000}{M o l a r i t y}$
$\Rightarrow Molar conductivity = \frac{\frac{1}{x} \times 1000}{y}$
$\Rightarrow Molar conductivity = \frac{1000}{x y}$
Hence, the correct option is C.

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